(x+y)(5x^2-2xy+4y^2)=

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Solution for (x+y)(5x^2-2xy+4y^2)= equation:


Simplifying
(x + y)(5x2 + -2xy + 4y2) = 0

Reorder the terms:
(x + y)(-2xy + 5x2 + 4y2) = 0

Multiply (x + y) * (-2xy + 5x2 + 4y2)
(x(-2xy + 5x2 + 4y2) + y(-2xy + 5x2 + 4y2)) = 0
((-2xy * x + 5x2 * x + 4y2 * x) + y(-2xy + 5x2 + 4y2)) = 0

Reorder the terms:
((4xy2 + -2x2y + 5x3) + y(-2xy + 5x2 + 4y2)) = 0
((4xy2 + -2x2y + 5x3) + y(-2xy + 5x2 + 4y2)) = 0
(4xy2 + -2x2y + 5x3 + (-2xy * y + 5x2 * y + 4y2 * y)) = 0
(4xy2 + -2x2y + 5x3 + (-2xy2 + 5x2y + 4y3)) = 0

Reorder the terms:
(4xy2 + -2xy2 + -2x2y + 5x2y + 5x3 + 4y3) = 0

Combine like terms: 4xy2 + -2xy2 = 2xy2
(2xy2 + -2x2y + 5x2y + 5x3 + 4y3) = 0

Combine like terms: -2x2y + 5x2y = 3x2y
(2xy2 + 3x2y + 5x3 + 4y3) = 0

Solving
2xy2 + 3x2y + 5x3 + 4y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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